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-rwxr-xr-xCS2501/trees/tree4.c87
1 files changed, 87 insertions, 0 deletions
diff --git a/CS2501/trees/tree4.c b/CS2501/trees/tree4.c
new file mode 100755
index 0000000..77b64d9
--- /dev/null
+++ b/CS2501/trees/tree4.c
@@ -0,0 +1,87 @@
+#include <stdlib.h>
+#include <string.h>
+#include <stdio.h>
+
+
+typedef struct node {
+ int id;
+ struct node *left;
+ struct node *right;
+} treenode;
+
+
+
+/* WRITE A RECURSIVE routine which swaps the
+ left and right child for every node in a given tree */
+/* will this operate in pre, in, or post order fashion?
+does it matter? if so, why does it matter? */
+
+rotate(t)
+treenode *t;
+{
+ treenode *tmp;
+ if(!t) return;
+ rotate(t->left);
+ rotate(t->right);
+ tmp = t->left;
+ t->left = t->right;
+ t->right = tmp;
+}
+
+
+preorder(t)
+treenode *t;
+{
+ if (!t) return;
+
+ printf("%d\n", t->id);
+ preorder(t->left);
+ preorder(t->right);
+}
+
+
+
+
+main (argc, argv, envp)
+int argc;
+char **argv, **envp;
+{
+ treenode *t;
+ t = malloc(sizeof(treenode));
+ /* build a binary tree with at least 6 nodes */
+ t->right = malloc(sizeof(treenode));
+ t->left = malloc(sizeof(treenode));
+ t->right->right = malloc(sizeof(treenode));
+ t->right->left = malloc(sizeof(treenode));
+ t->left->right = malloc(sizeof(treenode));
+ t->left->left = malloc(sizeof(treenode));
+
+ t->right->right->right = 0;
+ t->right->right->left = 0;
+ t->right->left->right = 0;
+ t->right->left->left = 0;
+ t->left->right->right = 0;
+ t->left->right->left = 0;
+ t->left->left->right = 0;
+ t->left->left->left = 0;
+
+ /* build a binary tree with at least 6 nodes */
+ t->id = 1;
+ t->right->id = 3;
+ t->left->id = 2;
+
+ t->right->right->id = 7;
+ t->right->left->id = 6;
+ t->left->right->id = 5;
+ t->left->left->id = 4;
+
+
+ /* build a binary tree with at least 6 nodes */
+
+ /* now show your rotate function works */
+ preorder(t);
+ rotate(t);
+ printf("\n");
+ preorder(t);
+
+}